Last updated: 25 September 2026, 10:44
National 5 · Mechanisms and Structures › Pneumatics

💨 Pneumatics — Course Notes

Pneumatic components, circuit diagrams, SAC and DAC circuits, speed control, and automatic circuits

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Section 1: What are Pneumatics?

Pneumatics is the use of pressurised air to do mechanical work. A compressor draws in air from the atmosphere and compresses it to a higher pressure. This compressed air is stored and then controlled to produce linear or rotary movement. Pneumatic systems are found all around us — in factory automation, bus door mechanisms, dental drills, road drills, and vehicle braking systems.

Infographic showing pneumatic systems found all around us — factory automation, bus door mechanisms, dental drills, road drills, and vehicle braking systems
Key point: Pneumatic systems are widely used in industry because compressed air is safe, clean, and readily available.
Safety: Isolate the air supply before connecting or disconnecting components. Never point a pneumatic line at anyone. Check all connections are secure before pressurising a circuit.

Advantages of pneumatic systems

Pneumatic systems offer several advantages over hydraulic or electrical systems: compressed air is non-flammable and safe to use in hazardous environments; the components are relatively low-cost; speed is easy to adjust using flow control valves; and any leaks result only in air escaping rather than fluid spillage.

Disadvantages

Pneumatic systems can be noisy, and energy is lost as heat when air is compressed. A compressor and air supply are always required. Pneumatic systems are usually limited to two fixed positions, set by mechanical stops — accurately stopping a piston partway between these stops is difficult, since air's compressibility lets it drift rather than staying rigidly in place.

✏️ Task 1 — Pneumatics in context

1a. Give three examples of pneumatic systems you might encounter in everyday life. For each one, describe what work the compressed air is doing.

Answer ✓ Saved

1b. Explain two advantages and two disadvantages of using a pneumatic system compared to an electric motor for a door-opening mechanism.

Answer ✓ Saved

Section 2: Pneumatic Components — Seeing it Work First

Rather than starting with a large number of symbols to memorise, let's watch a real circuit working first. Seeing the simulation below will give you a feel for what's going on — the air flowing, the valve switching, the cylinder moving — before we break down exactly why it behaves that way and what each part is called.

💨 No Pressure Sim — Single Acting Cylinder (SAC)
⛶ Full screen
Click on the component on the left and see what happens.

Clicking the push-button valve lets main air flow through to the cylinder, pushing the piston out — the outstroke. Releasing the button cuts off that air supply, and a spring inside the cylinder pushes the piston back in — the instroke — venting the used air out the other side of the valve as it goes.

Now let's look at what you just saw, piece by piece.

Main air supply and exhaust

Every pneumatic circuit needs a main air supply — the pressurised air from the compressor, connected into port 1 of a valve. Exhaust is where used air vents to atmosphere after passing through the circuit, shown in diagrams as an open triangle.

Photograph of a pneumatic compressor
Compressor
Produces the main air supply
Symbol for main air supply
Main Air Supply
Enters at port 1
Symbol for an exhaust port
Exhaust Port
Vents used air to atmosphere

The 3/2 valve

The valve you just operated is a push-button, spring-return 3/2 valve — it has 3 ports and 2 states.

We have to be specific about the full name, because a 3/2 valve can be switched from its normal state to its actuated state in several different ways. The number of ports and states tells you what the valve does; the actuator tells you how it gets triggered. The same 3/2 valve could instead be built as a roller 3/2 valve, a lever 3/2 valve, a pilot 3/2 valve, and so on — the switching behaviour is identical, but what causes the switch is different.

The word "actuate": in pneumatics, to actuate a valve means to trigger it to move from its normal (rest) state into its other state. The actuator is whatever causes that triggering to happen — a finger on a button, a cam tripping a roller, a small air pressure signal, and so on. A valve is described by both its ports/states and its actuator, e.g. "push-button, spring-return 3/2 valve".

Here are the actuators you'll meet across these notes:

Push-button actuator symbol
Push-button
Pressed by hand
Spring return symbol
Spring Return
Returns the valve to normal
Roller actuator symbol
Roller
Actuated while a moving part presses on it
Roller trip actuator symbol
Roller Trip
Actuated momentarily as a part passes over it
Lever actuator symbol
Lever
Operated by hand (or foot) and usually latches on
Plunger actuator symbol
Plunger
Pushed end-on
Pilot (main air) actuator symbol
Pilot
Switched by main air pressure
Diaphragm actuator symbol
Diaphragm
Switched by a small pressure change
See Section 7
Solenoid actuator symbol
Solenoid
Switched electrically
See Section 12

Here's what's actually happening inside a push-button, spring-return 3/2 valve as you press and release the button:

Worked Example — How the 3/2 valve switches
1
At rest: The valve is in its normal (spring-return) state. Port 1 (main air) is blocked; port 2 (cylinder) is connected to port 3 (exhaust). The cylinder spring holds the rod instroked.
2
Button pressed: The valve shifts to its actuated state. Main air at port 1 now connects to port 2 (cylinder). Port 3 (exhaust) is blocked. Pressurised air causes the outstroke against the spring.
3
Button released: The valve spring returns it to its normal state. Port 2 connects back to port 3 (exhaust). Air vents to atmosphere and the cylinder spring instrokes the rod.

Single acting cylinder (SAC)

The cylinder in the simulation is a single acting cylinder (SAC). Main air causes the outstroke (extension of the piston rod); a spring returns it when the pressure is released. SACs are used where force is only needed in one direction.

Photograph of a single acting cylinder, labelled: single air port — compressed air entry from a valve to out-stroke the piston
Schematic drawing: You've just met your first valve and cylinder. In your assessment, you will not need to draw a component completely from scratch — but you will be given circuit layout diagrams to read, and you'll often need to complete a partly-drawn circuit, for example adding in missing piping between components.

It is therefore useful to be able to recognise symbols and know how they are connected — and the best way to learn to do this is to practice drawing the symbols and circuits yourself. That's why these notes include drawing tasks marked ✏️ throughout. For these, sketch your answer by hand on paper, then photograph or scan it and paste the image directly into the answer box (click inside the box, then paste as you would with text).
✏️ Task 2 — Main air, exhaust, the 3/2 valve and the SAC

2a. Use the No Pressure simulator or physical components to build the SAC circuit. Operate the push-button valve and describe what happens. In your answer, describe the state of the valve and what the cylinder does when the button is pressed and when it is released.

Answer ✓ Saved

2b. Describe what happens to the ports of a 3/2 valve when it switches from its normal state to its actuated state.

Answer ✓ Saved

2c. ✏️ Draw the full circuit diagram for the SAC circuit: a 3/2 push-button valve (normal position) connected to a single acting cylinder, with main air and exhaust labelled. Zoom into the symbols in the simulator above (or click on the exemplar below) to check the details of how to draw them. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 2c 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 3: T-Piece — Splitting the Air Supply

A T-piece connector lets one main air supply feed two or more branches of a circuit at once. See it in action below.

💨 No Pressure Sim — T-Piece Air Supply Splitting
⛶ Full screen
Observe how the T-piece distributes the main air supply to two separate branches simultaneously.

Both branches receive the same supply pressure. T-pieces are used when a single air source needs to power multiple cylinders or valves at the same time.

✏️ Task 3 — T-piece

3a. Use the simulator or physical components to build a circuit using a T-piece to operate two cylinders from the same main air supply. Describe what you observe. What happens to each cylinder when the valve is operated?

Observations ✓ Saved

3b. Give one example of a practical application where a T-piece would be useful in a pneumatic circuit.

Answer ✓ Saved

Section 4: Shuttle Valve (OR control)

A shuttle valve lets a cylinder be operated from two separate control valves — actuating either one, or both together, causes the outstroke. This is known as OR control.

💨 No Pressure Sim — Shuttle Valve
⛶ Full screen
One valve is a push-button, the other is a lever valve set to latch. Latch the lever valve on, then also press the push-button — notice the shuttle valve lets air through to the cylinder whether just one valve is actuated, or both are actuated at the same time.

Inside the shuttle valve is a small ball. When main air enters from one inlet, it pushes the ball across to seal the other inlet and passes through to the outlet. If main air enters the other inlet instead, the ball moves the other way and the same thing happens. If main air enters both inlets at the same time, the ball stays where it is and main air still passes through to the outlet.

You might wonder why a plain T-piece couldn't be used here instead, since it also joins two pipes together. A T-piece has no ball or seal inside it — it's just an open junction. If only one of the two valves were actuated, the main air would take the path of least resistance and simply escape out through the other valve's exhaust port, instead of reaching the cylinder. A shuttle valve prevents this by sealing off whichever inlet isn't currently supplying air.

Key point: A shuttle valve lets the cylinder outstroke if valve A or valve B (or both together) supplies main air — this is called OR control. It's useful for two-handed operation or operating a machine from two different locations.
✏️ Task 4 — Shuttle valve

4a. Explain how a shuttle valve works. What happens inside the valve when main air enters from one inlet? What happens if main air enters from both inlets at the same time?

Answer ✓ Saved

4b. A press in a workshop can be dangerous to operate with one hand. Describe how a shuttle valve could be used as part of a two-handed safety circuit.

Answer ✓ Saved

4c. ✏️ Draw the circuit symbol for a shuttle valve, clearly showing its two inlets and single outlet. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 4c 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 5: AND Control

Section 4 covered OR control — where valve A or valve B (or both valves) are actuated to outstroke a cylinder. Sometimes you want a cylinder to only outstroke if two conditions are both satisfied at once. This is called AND control.

Where AND control is used

The classic example is a two-handed safety control on a machine like a guillotine or a press. If the machine only needed one button pressed, an operator could reach into the danger area with their free hand while pressing the button with the other. Setting up the machine so that both buttons — one for each hand — must be pressed at the same time guarantees both of the operator's hands are safely out of the way before the machine can move.

Other examples include a machine guard that must be closed and a start button pressed before a cylinder will move, or a security gate that needs a card swipe and a button press together.

Key point: OR control needs a specific component (a shuttle valve) but AND control can be built using two ordinary 3/2 valves, but they have to be arranged in a specific way.
✏️ Task 5 — Design an AND control circuit

5a. ✏️ Using two 3/2 push-button, spring-return valves and a single acting cylinder, design a circuit where the cylinder will only outstroke when both push-buttons are pressed at the same time. Pressing only one button (either one) must not cause the outstroke. Clue: you only need one main air supply. Draw your circuit by hand and paste a photo of it here.

Thumbnail of an exemplar answer for task 5a 🔍 Try the design yourself first — then click here to compare against an exemplar answer
Design ✓ Saved

5b. Build or simulate your design. Test what happens when you press only the first button, only the second button, and both together. Describe what you observed for each test.

Test evidence ✓ Saved

5c. Explain, in terms of the path the main air has to take, why pressing only one of the two valves does not cause the cylinder to outstroke.

Answer ✓ Saved

Section 6: Speed Control — Restrictors

In many applications it is necessary to control the speed that the cylinder moves. This is achieved by restricting the flow of air.

The restrictor

A restrictor slows a cylinder down by reducing the amount of space the air can flow through — a small adjustable screw narrows the passage, so less air can get through per second. The narrower you make it, the slower the cylinder moves.

Photograph of a restrictor
Restrictor
Adjustable flow control valve
Problem with a plain restrictor: it narrows the passage in both directions at once. That slows the cylinder down whichever way it's moving — outstroke and instroke — when we usually only want to control one direction. It can also make the piston's movement jerky rather than smooth.

The uni-directional restrictor (UDR)

A uni-directional restrictor solves this by combining the same adjustable restriction with a one-way bypass channel running alongside it. The bypass contains a small flap or ball that acts like a one-way valve:

Diagram showing a uni-directional restrictor in both directions — left: air flow from port 1 to port 2 is blocked from the bypass and forced through the restriction; right: air flow from port 2 to port 1 is free to bypass the restriction
  • In the left-hand diagram, air is trying to flow from port 1 to port 2. The flap is pushed shut, blocking the bypass channel, so the air is forced through the narrow adjustable orifice — this direction is restricted.
  • In the right-hand diagram, air is flowing the other way, from port 2 to port 1. This pushes the flap open, so the air flows straight through the wide bypass channel instead — this direction is not restricted.

That's why it's called uni-directional: free flow one way, restricted flow the other — set by the single adjustable screw.

Where to put it

A UDR is placed so that it restricts the air leaving the cylinder (the exhaust side), not the air coming in. If you restrict the incoming air instead, the piston has to fight to build up enough pressure to move at all, while the opposite side empties out freely — this makes the motion hesitant and jerky. Restricting the exhaust instead means main air can still push in freely, and the piston is held back smoothly by air trapped behind it, controlled by how fast it's allowed to escape.

Exam rule: In pneumatics, always restrict the exhaust air leaving a cylinder — never the main air going in. This is what gives smooth, controlled movement.
💨 No Pressure Sim — SAC with Restrictors
⛶ Full screen
Now try it yourself — adjust the restrictors and observe how they control the cylinder's speed.
✏️ Task 6 — Speed control

6a. Use the simulator or physical components to build a circuit with a UDR. Adjust the restrictor and observe how the cylinder speed changes. Explain, using the idea of the bypass channel, why a UDR only restricts the airflow in one direction.

Answer ✓ Saved

6b. A packaging machine uses a SAC to push items along a conveyor. The operator wants the outstroke to be slow but the instroke to be quick. Explain where a uni-directional restrictor (UDR) should be placed and how it should be oriented to achieve this.

Answer ✓ Saved

6c. ✏️ Draw a SAC circuit with a uni-directional restrictor correctly positioned on the exhaust to slow the outstroke. Label the direction of free flow and restricted flow. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 6c 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 7: Air Bleed (Diaphragm) Circuit

An air bleed circuit works differently from every circuit so far — instead of pressing a valve to supply air, it works by blocking a small continuous flow of air. Try it in the simulator before reading the detail.

💨 No Pressure Sim — Air Bleed Circuit
⛶ Full screen
Click on the bleed point to cover it. Watch how pressure builds behind the diaphragm and triggers the cylinder outstroke. Release to see the cylinder instroke automatically.

How it works

The circuit uses a diaphragm-actuated 3/2 valve. In the normal state, main air constantly bleeds to atmosphere through a small hole in the circuit (the bleed point). Because this air is always escaping, there is never enough pressure to act on the diaphragm — the valve stays in its normal state and the cylinder remains instroked.

A uni-directional restrictor (UDR) is fitted between the main air supply and the bleed nozzle. Adjusting it controls how freely air is allowed to escape at rest, which lets the circuit be tuned to suit whatever is being sensed — open it up for something that blocks the nozzle firmly and completely, or wind it in so that even the lightest, most fleeting obstruction is enough to build up pressure and switch the valve.

When an object covers the bleed hole, the escaping air is blocked. Pressure immediately builds up behind the diaphragm. Once it reaches the switching threshold, the diaphragm switches the 3/2 valve, main air flows to the cylinder, and the cylinder outstrokes.

As soon as the obstruction is removed, air bleeds away again, pressure drops, the diaphragm releases, and the valve spring returns it to its normal state — causing the cylinder to instroke.

Key point: The air bleed circuit is a proximity/presence detection circuit. No electrical signal is needed — physical contact or proximity blocking the bleed hole is enough to trigger the cylinder. This makes it useful for detecting products on a conveyor, detecting when a hand is near a machine, or triggering an action when a part arrives at a station. Because it needs only a change in air pressure and no physical contact from a sensor, it's especially useful for detecting delicate or fragile items — such as eggs or electronic circuit boards — where a mechanical touch sensor could easily damage them.
Air bleed circuit diagram showing a diaphragm-actuated 3/2 valve and SAC
✏️ Task 7 — Air bleed circuit

7a. Explain how an air bleed circuit works. In your answer, describe what happens at the bleed point when it is open, and what happens when it is blocked.

Answer ✓ Saved

7b. Describe one practical application of an air bleed circuit. Explain what causes the bleed to be blocked in your example and what action this triggers.

Answer ✓ Saved

7c. State one key difference between an air bleed circuit and a standard push-button SAC circuit.

Answer ✓ Saved

7d. ✏️ Draw the full air bleed circuit: including the diaphragm-actuated 3/2 valve, the bleed point, main air, exhaust, and the single acting cylinder. Try to do this as best you can from memory before you look at the simulator or solution below. Draw by hand and paste a photo of your drawing here — then check it against the diagram above.

Thumbnail of an exemplar answer for task 7d 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 8: Double Acting Cylinder Circuit

So far, we've been working with cylinders that only need to be controlled in one direction. A spring has returned the piston to where it started. However, we often need to control both the outstroke and instroke of a cylinder. To do this, we use a double acting cylinder (DAC) that has a port at each end. Let's consider using 3/2 valves to directly control the air going into each end of a DAC.

The problem with two 3/2 valves

Imagine connecting one 3/2 push-button valve to the outstroke side of a DAC, and a second 3/2 push-button valve to the instroke side. Pressing the first button lets main air push the piston out; pressing the second lets main air push it back in.

This sounds reasonable, but it relies entirely on the operator pressing exactly one button at a time, in the right order. Press both together, or release both, and neither side of the piston is being actively driven — the cylinder just sits wherever it happens to be, with nothing holding it firmly in position. There's nothing in the circuit itself that prevents this.

What we actually need: a valve that guarantees exactly one side of the piston is connected to main air at all times, with the other side always exhausting — automatically, from a single action, without relying on an operator to coordinate two separate valves correctly.

That's exactly what a 5/2 directional control valve does. Because it only ever has two possible states, and each state connects main air to one side while exhausting the other, it's physically impossible for both sides (or neither side) to be pressurised at once. Try it in the simulator below.

💨 No Pressure Sim — Double Acting Cylinder (DAC)
⛶ Full screen
Operate the 5/2 valve by clicking on the 3/2 valve on each side. Look carefully at the arrows on the 5/2 valve that represent air channels through the component. Notice that main air is connected to one or other end of the DAC at all times. The other DAC port is connected to exhaust.
Key point: Air that has been controlled by a valve, and then goes on to control another valve, is known as pilot air. On a circuit diagram, pilot air is drawn as a dashed line, so you can tell it apart from the solid lines used for main air and exhaust.
Photograph of a double acting cylinder

A 5/2 valve has five ports and two states. In one state, port 1 (main air) connects to port 2 (outstroke side) while port 4 (instroke side) exhausts through port 5. Switching the valve reverses this: port 1 now connects to port 4, while port 2 exhausts through port 3. Changing the state of the valve therefore reverses the direction of the cylinder — and at every moment, one side is under pressure while the other is venting.

DAC advantage over SAC: Because main air actively drives the instroke as well as the outstroke, a DAC can produce a pushing force in both directions. The instroke force is slightly less than the outstroke force because the piston rod reduces the effective area on the instroke side (see Section 13).
✏️ Task 8 — DAC circuit

8a. Use the No Pressure simulator or physical components to build the DAC circuit. Operate the 5/2 valve in both directions. Describe what you observe and explain how the DAC differs from the SAC circuit you built in Task 2.

Observations ✓ Saved

8b. A DAC circuit has its 5/2 valve in the initial state. Describe what the cylinder is doing. Explain what happens to the cylinder when the valve changes to its actuated state.

Answer ✓ Saved

8c. ✏️ Draw the full circuit diagram for a DAC circuit: a 5/2 push-button valve operated by two 3/2 valves, connected to a double acting cylinder, with the ports numbered. Zoom into the symbols in the simulator above (or click on the exemplar below) to check the details of how to draw them. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 8c 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 9: Semi-Automatic Circuit

A semi-automatic circuit needs a manual input to start each cycle, but part of the operation happens automatically.

💨 No Pressure Sim — Semi-Automatic Circuit
⛶ Full screen
Press the 3/2 valve on the left hand side in the simulator below and watch the full cycle before reading how it works.

The cylinder extends (outstroke), then automatically retracts (instroke) when it reaches the end stop. The circuit then waits for your next button press.

A typical arrangement uses a DAC, a 5/2 valve with pilot actuators, and a roller spring-return valve triggered by the cylinder rod at the end of its outstroke.

Worked Example — Semi-automatic cycle
1
Start: Operator presses push-button → a pilot signal is sent to the 5/2 valve which causes it to change to its actuated state → main air flows to the outstroke side (port 2) of the DAC → cylinder outstroke begins.
2
End of outstroke: Rod actuates the 3/2 roller spring-return valve → a pilot signal is sent to the 5/2 valve and it returns to its normal state → main air causes the DAC to instroke → outstroke side exhausts through port 3.
3
Wait: Cylinder fully instroked. Circuit waits for operator to press button again to start the next cycle.
✏️ Task 9 — Semi-automatic circuit

9a. Describe the complete operating cycle of a semi-automatic pneumatic circuit. Include reference to: the pilot signal, how main air causes the outstroke, what triggers the instroke, and what happens at the end of the cycle.

Answer ✓ Saved

9b. Explain the difference between a manual circuit and a semi-automatic circuit. Give one advantage of using a semi-automatic circuit in a production environment.

Answer ✓ Saved

Section 10: Fully Automatic Circuit

A fully automatic circuit repeats its cycle continuously without any manual input after the initial start signal.

💨 No Pressure Sim — Fully Automatic Circuit
⛶ Full screen
Watch the continuous cylinder cycle in the simulation below. Each limit valve sends a pilot signal to trigger the next stroke — the circuit repeats without further operator input.

This automatic cycle would continue until main air is cut off.

Fully automatic vs semi-automatic: In a semi-automatic circuit, only one limit valve is used so the cylinder stops and waits at the instroked position. In a fully automatic circuit, a second limit valve at the instroked end immediately sends a pilot signal to trigger the next outstroke.
✏️ Task 10 — Fully automatic circuit

10a. Explain the role of each limit valve in a fully automatic circuit. What would happen if the limit valve at the retracted position were removed?

Answer ✓ Saved

10b. A fully automatic circuit is used in a bottling plant to cap bottles on a conveyor. Describe how the circuit could be modified to allow an operator to stop the machine safely at the end of a cycle (not mid-stroke).

Answer ✓ Saved

Section 11: Time Delay Circuit

A time delay valve introduces a controllable delay between an input signal and an output action.

💨 No Pressure Sim — Time Delay Circuit
⛶ Full screen
Click on the 3/2 valve on the left hand side to outstroke the DAC. Then keep the 3/2 valve on the right hand side pressed and watch the reservoir fill gradually. The cylinder only extends once reservoir pressure reaches the pilot threshold — demonstrating the time delay in action.

The circuit consists of a uni-directional restrictor feeding a reservoir, which builds up main air pressure slowly until it is high enough to pilot (switch) a 3/2 output valve. By adjusting the restrictor, the fill time of the reservoir — and therefore the length of the delay — can be changed. Increasing the size of the reservoir will also increase the delay time, as more volume must be filled before the pilot threshold is reached. When the input signal is removed, the reservoir vents quickly back through the UDR and the timer resets immediately.

✏️ Task 11 — Time delay circuit

11a. Describe how a pneumatic time delay circuit produces a time delay. Include reference to the restrictor, reservoir, and pilot-operated output valve.

Answer ✓ Saved

11b. A time delay circuit is set to delay for 3 seconds. An engineer wants to increase the delay to 8 seconds. Explain two ways this could be achieved.

Answer ✓ Saved

11c. Use the simulator or physical components to build a time delay circuit. Adjust the UDR to make the delay longer and shorter. Describe what you observe and explain why adjusting the restrictor changes the delay time.

Observations ✓ Saved

11d. Describe one practical application of a time delay circuit in an industrial or domestic context. Explain what the delay achieves in your chosen example.

Answer ✓ Saved

11e. ✏️ Draw the two key components that generate a time delay in a pneumatics circuit. Label the components and the direction of air flow. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 11e 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 12: Electrical Control of Pneumatics

Every circuit so far has been switched by hand, by a pilot air signal, or automatically by another part of the pneumatic circuit. A pneumatic valve can also be switched electrically, using a solenoid actuator — a coil that, when energised, moves the valve's spool. This is how pneumatic systems are controlled by microcontrollers, Programmable Logic Controllers (PLCs) and other electronic systems.

A solenoid-actuated valve is connected to an electrical control system (such as a microcontroller or PLC). When the control system sends an electrical signal to the solenoid, it switches the valve and main air flows to the cylinder. When the electrical signal is removed, the spring returns the valve to its normal state and the cylinder instrokes. This allows a pneumatic circuit to be controlled entirely by software or by electronic sensors such as light gates or pressure switches.

Solenoid-controlled SAC circuit diagram showing electrical signal triggering a solenoid valve which causes the cylinder to outstroke
Key point: A solenoid valve is the bridge between the electronic and pneumatic worlds. Everywhere you'd otherwise need a person to press a button or a mechanical pilot signal, a solenoid lets a microcontroller, sensor, or PLC do the switching instead.
✏️ Task 12 — Electrical control

12a. Explain the difference between a pilot actuator and a solenoid actuator on a valve. In which type of circuit would each be used?

Answer ✓ Saved

12b. Give one example of a sensor that could be used to trigger a solenoid valve electrically, and describe the pneumatic action it would cause.

Answer ✓ Saved

12c. ✏️ Draw the full solenoid circuit diagram: a solenoid-actuated 3/2 valve connected to a single acting cylinder, labelling the electrical signal, main air and exhaust. Draw by hand and paste a photo of your drawing here.

Thumbnail of an exemplar answer for task 12c 🔍 Click to see an exemplar answer
Drawing ✓ Saved

Section 13: Calculating Cylinder Force

The force a pneumatic cylinder can produce depends on two things: the air pressure in the circuit, and the area of the piston that the pressure is acting on.

F = P × A
Force (N) = Pressure (N/mm²) × Area (mm²)

You can rearrange this formula to find any of the three quantities. The FPA triangle is a useful memory aid:

F P A

Cover the quantity you want to find — the other two show how to calculate it.

F = P × A
P = F / A
A = F / P
Watch your units: In National 5 Engineering Science, pressure is given in N/mm² and diameters in mm — this means no conversion is needed: work in millimetres throughout and your force comes out directly in Newtons. (You may see pressure quoted elsewhere in bar or pascals, but you won't be asked to convert between these units.)

Piston area and rod area

A single acting cylinder only has main air pushing on one side of the piston (the outstroke). The full circular face of the piston is available to push against, so the effective area is simply the piston area:

A = π × D²4
where D is the diameter of the piston

Engineers use the diameter of the piston (rather than its radius) mainly because diameter is what's easy to measure in the workshop — you can measure straight across a piston or a rod with a pair of callipers (or a vernier calliper) far more easily and accurately than you could measure to the centre for a radius.

A double acting cylinder has main air pushing on both sides of the piston, one side at a time. On the outstroke, the full piston area is available — exactly like a SAC. On the instroke, main air acts on the other side of the piston, but the piston rod takes up part of that face, so the effective area is the piston area minus the rod area.

A
Outstroke — full piston area
Main air pushes on the whole piston face:
piston area = π × D² / 4
rod, d A−a
Instroke — piston area minus rod area
rod area = π × d² / 4
effective area = piston area − rod area
What each letter means
D
diameter of the piston
d
diameter of the rod
A
piston area — the full circular face of the piston
a
rod area — the cross-section of the piston rod
Key point: Because the effective area on the instroke (piston area minus rod area) is smaller than the piston area used on the outstroke, a DAC always produces less force on the instroke than on the outstroke, for the same supply pressure.

Worked Example 1 — outstroking and instroking force

Diagram of a DAC piston showing a 70mm piston diameter and a 10mm piston rod diameter, with a cross-section view and an isometric view of the cylinder

The cylinder above has a piston diameter of 70 mm and a piston rod diameter of 10 mm. It is supplied at 0.5 N/mm². Calculate the outstroking force and the instroking force.

Outstroking force
1
Piston area: A = π × 70² / 4 = 3848 mm².
2
Force: F = P × A = 0.5 × 3848 = 1924 N.
Instroking force
1
Rod area: a = π × 10² / 4 = 78.5 mm².
2
Effective area: piston area − rod area = 3848 − 78.5 = 3770 mm².
3
Force: F = P × A = 0.5 × 3770 = 1885 N.

Worked Example 2 — calculating piston diameter

A door requires a force of 354 N to slide it open. A single acting cylinder supplied at a pressure of 0.5 N/mm² controls the operation. Calculate the minimum diameter of piston required.

Piston diameter
1
Rearrange the formula to find area: A = F / P.
2
Area: A = 354 / 0.5 = 708 mm².
3
Rearrange the area formula to find diameter: D = √(4A / π).
4
Diameter: D = √(4 × 708 / π) = √901.4 = 30.0 mm.

Worked Example 3 — calculating supply pressure

A stamping machine exerts a force of 454 N with a piston diameter of 34 mm. Calculate the air pressure required.

Supply pressure
1
Piston area: A = π × 34² / 4 = 907.9 mm².
2
Rearrange the formula to find pressure: P = F / A.
3
Pressure: P = 454 / 907.9 = 0.5 N/mm².
✏️ Task 13 — Force calculations

13a. A SAC has a piston diameter of 20 mm and is supplied at 0.4 N/mm². Calculate the outstroke force in Newtons. Show your working.

Answer ✓ Saved

13b. A DAC has a piston diameter of 40 mm and a piston rod diameter of 12 mm, supplied at 0.6 N/mm². Calculate (i) the outstroking force and (ii) the instroking force. Show your working for both, including the piston area and the rod area.

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13c. Explain, in terms of piston area and rod area, why a DAC's instroking force is always lower than its outstroking force at the same supply pressure.

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13d. A single acting cylinder must produce a force of 250 Newtons when supplied at 0.5 N/mm². Calculate the minimum piston area required. Show your working.

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13e. A double acting cylinder has a piston diameter of 32 mm. Calculate the supply pressure required to produce an outstroke force of 643 Newtons. Show your working.

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Section 14: Design Challenges

The questions in Sections 1–12 checked that you understand each circuit individually. The three challenges below work differently — each one gives you a real-world context and a written specification, the same way an assignment does. Nobody will show you the circuit first: you have to work out which components to use and how to connect them, then build or simulate your design and check it actually meets the spec.

How to approach these: Read the whole specification before you draw anything. Underline the key words that tell you which component you need ("either... or" usually means a shuttle valve; "slowly and smoothly" means a restrictor on the exhaust; "after a delay" means a time delay circuit). Sketch a rough plan first, then tidy it into a proper circuit diagram.

Design Challenge 1 — Car wash spray arm

A car wash has a spray arm, powered by a double acting cylinder, that swings out over each car. If the arm swings out too fast it splashes water everywhere, so it needs to move out slowly and under control. Once the wash is finished, the arm should retract quickly out of the way so the next car can pull in.

iPressing push-button A must cause the cylinder to outstroke slowly and smoothly.
iiPressing push-button B must cause the cylinder to instroke at normal (unrestricted) speed.
iiiThe circuit must not restrict the main air supply into the cylinder at any point.
✏️ Design Challenge 1

DC1a. Design a pneumatic circuit to meet the specification above. You must identify every component, valve and actuator, and show the connections between them. Draw by hand and paste a photo of your design here.

Design ✓ Saved

DC1b. Build or simulate your design and test it. Describe what actually happened when you pressed each button, and paste a photo or screenshot of your working circuit here.

Test evidence ✓ Saved

DC1c. Evaluate your circuit against each point of the specification. For each point, state whether it is met and justify your answer.

Evaluation ✓ Saved
Thumbnail of an exemplar answer for Design Challenge 1 🔍 Try the design yourself first — then click here to compare against an exemplar answer

Design Challenge 2 — Greenhouse roof vent

A commercial greenhouse has a long roof vent, opened and closed by a double acting cylinder, that needs to be controlled from either end of the greenhouse — whichever member of staff is closest should be able to open it, without needing to know whether someone at the other end is also about to use it.

iThe cylinder must outstroke (open the vent) when push-button valve 1 or push-button valve 2 is actuated, whether the other is actuated or not.
iiThe cylinder must instroke (close the vent) when a third push-button valve is actuated.
✏️ Design Challenge 2

DC2a. Design a pneumatic circuit to meet the specification above. You must identify every component, valve and actuator, and show the connections between them. Draw by hand and paste a photo of your design here.

Design ✓ Saved

DC2b. Build or simulate your design. Test it with valve 1 alone, valve 2 alone, and both together. Paste a photo or screenshot of your working circuit here, with a note of what you observed for each test.

Test evidence ✓ Saved

DC2c. A colleague suggests replacing the shuttle valve with a simple T-piece, since "it also joins two pipes together." Explain why this would not work.

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DC2d. Can you suggest a design improvement? This should make the solution better than is specified.

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Thumbnail of an exemplar answer for Design Challenge 2 🔍 Try the design yourself first — then click here to compare against an exemplar answer

Design Challenge 3 — Car park barrier

An automatic barrier at a car park entrance is raised by a double acting cylinder. When a driver presses a button, the barrier should raise. Once fully raised, it should stay up just long enough for the car to pass, then lower automatically by itself — without the driver having to press anything else.

iPressing the entry button must cause the cylinder to outstroke, raising the barrier.
iiOnce the barrier reaches the fully raised position, an adjustable time delay of a few seconds must occur.
iiiAfter the delay, the cylinder must instroke automatically, lowering the barrier, with no further input from the driver.
Hint: think about how you detected "fully raised" in the semi-automatic and fully-automatic circuits in Sections 9 and 10, and how you produced a delay in Section 11 — this challenge combines both ideas.
✏️ Design Challenge 3

DC3a. Design a pneumatic circuit to meet the specification above. You must identify every component, valve and actuator, and show the connections between them. Draw by hand and paste a photo of your design here.

Design ✓ Saved

DC3b. Build or simulate your design and test it. Describe what happened, and paste a photo or screenshot of your working circuit here.

Test evidence ✓ Saved

DC3c. Evaluate your circuit against each point of the specification, stating whether it is met and justifying your answer. Then suggest one improvement that would make the barrier safer for a car that is still underneath it when the delay ends.

Evaluation ✓ Saved
Thumbnail of an exemplar answer for Design Challenge 3 🔍 Try the design yourself first — then click here to compare against an exemplar answer
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